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zh:notes:exponential_family

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zh:notes:exponential_family [2017/04/24 16:12]
pzczxs [Covariance of $\vec{u}(\vec{x})$]
zh:notes:exponential_family [2022/06/30 11:33] (当前版本)
pzczxs 讨论状态变化了
行 58: 行 58:
   \nabla \nabla \ln g(\vec{\eta}) & = & \nabla \frac{\nabla g(\vec{\eta})}{g(\vec{\eta})} \nonumber \\   \nabla \nabla \ln g(\vec{\eta}) & = & \nabla \frac{\nabla g(\vec{\eta})}{g(\vec{\eta})} \nonumber \\
   & = & \frac{1}{g(\vec{\eta})} \nabla \nabla g(\vec{\eta}) - \left[ \frac{1}{g(\vec{\eta})} \nabla g(\vec{\eta}) \right] \left[ \frac{1}{g(\vec{\eta})} \nabla g(\vec{\eta}) \right]^{\mathrm{T}} \nonumber \\   & = & \frac{1}{g(\vec{\eta})} \nabla \nabla g(\vec{\eta}) - \left[ \frac{1}{g(\vec{\eta})} \nabla g(\vec{\eta}) \right] \left[ \frac{1}{g(\vec{\eta})} \nabla g(\vec{\eta}) \right]^{\mathrm{T}} \nonumber \\
-  & = & \frac{1}{g(\vec{\eta})} \nabla \nabla g(\vec{\eta}) - \mathbb{E}[\vec{u}(\vec{x})] \mathbb{E}[\vec{u}(\vec{x})]^{\mathrm{T}} \label{log-second-derivative}+  & = & \frac{1}{g(\vec{\eta})} \nabla \nabla g(\vec{\eta}) - \mathbb{E}[\vec{u}(\vec{x})] \mathbb{E}[\vec{u}(\vec{x})^{\mathrm{T}}\label{log-second-derivative}
 \end{eqnarray} \end{eqnarray}
  
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 \begin{eqnarray} \label{log-second} \begin{eqnarray} \label{log-second}
-  \frac{1}{g(\vec{\eta})} \nabla \nabla g(\vec{\eta}) & = & \nabla \nabla \ln g(\vec{\eta}) + \mathbb{E}[\vec{u}(\vec{x})] \mathbb{E}[\vec{u}(\vec{x})]^{\mathrm{T}}+  \frac{1}{g(\vec{\eta})} \nabla \nabla g(\vec{\eta}) & = & \nabla \nabla \ln g(\vec{\eta}) + \mathbb{E}[\vec{u}(\vec{x})] \mathbb{E}[\vec{u}(\vec{x})^{\mathrm{T}}]
 \end{eqnarray} \end{eqnarray}
  
行 70: 行 70:
  
 \begin{eqnarray} \label{covariance} \begin{eqnarray} \label{covariance}
-  ​+  ​- \nabla \nabla \ln g(\vec{\eta}) & = & \mathbb{E}[\vec{u}(\vec{x}) \vec{u}(\vec{x})^{\mathrm{T}}] - \mathbb{E}[\vec{u}(\vec{x})] \mathbb{E}[\vec{u}(\vec{x})^{\mathrm{T}}] = \mathrm{cov}[\vec{u}(\vec{x})]
 \end{eqnarray} \end{eqnarray}
 +
 +~~DISCUSSION:​closed~~
zh/notes/exponential_family.1493021530.txt.gz · 最后更改: 2017/04/24 16:12 由 pzczxs